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0=20x+50x-4.9x^2
We move all terms to the left:
0-(20x+50x-4.9x^2)=0
We add all the numbers together, and all the variables
-(20x+50x-4.9x^2)=0
We get rid of parentheses
4.9x^2-20x-50x=0
We add all the numbers together, and all the variables
4.9x^2-70x=0
a = 4.9; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·4.9·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*4.9}=\frac{0}{9.8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*4.9}=\frac{140}{9.8} =14+2.8/9.8 $
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